| (9.11) |
Now we show is true if and only if
is connected.
Suppose is connected. The continuous image of a connected space is
connected, so
is connected. The connected subsets of
are precisely the singletons, so we know
, indicating
is constant.
Conversely, suppose is not connected. It is possible to define a
continuous function which is non-constant by separating
and defining
and
. The open sets in
are
precisely the singletons, so any preimage equals
,
, or is trivial,
so that
is continuous. Therefore if
is connected, every
continuous function
is constant.