Now begin the problem.
Proof.
Note that

converges uniformly on the set disk

to
 |
(3.49) |
Solve for the zeroes:
![$\displaystyle 0=z^2 - \frac{2z}{3-z} = z^2(3-z) - 2z
= z\left[z(3-z)-2\right]
= z[-z^2 + 3z - 2]
= -z(z-1)(z-2)$](img465.svg) |
(3.50) |
Only two of the roots

and

lie inside the contour

.
None of the roots lie on the contour, which
indicates

where the minimum is taken
over

.
Now we can apply the Rouché theorem with
as defined above,
and
. On the contour
, let us verify the inequality.
Let
be such that
for all and in the disk |
(3.51) |
Then
 |
 |
(3.52) |
| |
 |
(3.53) |
| |
 |
(3.54) |
| |
 |
(3.55) |
| |
 |
(3.56) |
Since

and

, this shows that Rouché's
theorem applies, indicating

and

have the same number of
roots, namely 2, inside the contour

.